(16)

A number is divisible by 6 when it is divisible by 2 and 3 both.

The three digit number can be ab2.

a + b can be 4, 7,10

If a + b = 4 then (a, b) can be (1,3), (3,1), (2, 2)

If a + b = 7 then (a, 6) can be(2, 5), (5, 2), (3,4), (4,3)

If a + b = 10 then (a, 6) can be (5, 5)

So, 8 such cases when 2 is at unit's place

Similarly, there exist 8 such cases when 4 is at unit's place.

Total = 16 cases.

Hence this is the required answer.

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